55x^2+42x-49=0

Solution for 55x^2+42x-49=0 equation:

55x^2+42x-49=0

a = 55; b = 42; c = -49;
Δ = b2-4ac
Δ = 422-4·55·(-49)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-112}{2*55}=\frac{-154}{110}
=-1+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+112}{2*55}=\frac{70}{110}
=7/11
$